Hmmm, which windows OS are you using. Mine's a windows XP.

OK, so you invoked pypy-c using the full pathname of the executable?
I tried it by adding the pypy-1.0.0 to the system PATH variable and just
using 'pypy-c'. I should have tried it your way  :headdesk:    :)

Raj

On Oct 21, 2007, at 7:59 PM, Christian Tismer wrote:

I tested this right now.

D:\tmp\pypy-1.0.0-win32\pypy-1.0.0>pypy-c
Python 2.4.1 (pypy 1.0.0 build 41438) on win32
Type "help", "copyright", "credits" or "license" for more information.
import pickle
pickle.__file__
'D:\\tmp\\pypy-1.0.0-win32\\pypy-1.0.0\\share\\pypy-1.0\\lib-python\ \modified-2.4.1\\pickle.py'


Tried it from a different folder as well:

D:\tmp\pypy-1.0.0-win32\pypy-1.0.0>cd \pypy

D:\pypy>\tmp\pypy-1.0.0-win32\pypy-1.0.0\pypy-c.exe
Python 2.4.1 (pypy 1.0.0 build 41438) on win32
Type "help", "copyright", "credits" or "license" for more information.
import pickle
pickle.__file__
'\\tmp\\pypy-1.0.0-win32\\pypy-1.0.0\\share\\pypy-1.0\\lib-python\ \modified-2.4.1\\pickle.pyc'


Looks all pretty good so far.

What else should I try for validation?
The basic stuff appears to be in place.

cheers - chris

'Sam, how far do we have to go?'
'I don't know, Mr. Frodo', said Sam
'because I don't know where we're going'.

-- JRR Tolkien, Return of the King

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