you need to point to the actual file location of pypy-c, such as ../goal/pypy-c.
On Sat, Feb 11, 2012 at 5:59 PM, kracekumar ramaraju
<kracethekingma...@gmail.com> wrote:
>
> Hi
>
> I am on ubuntu 11.10 on 32 bit OS. I ran all the procedures to get sanbox
> env.
>
> Now I am unable to run sandboxed interpreter.
>
> kracekumar@python-lover:~/pypy-pypy-2346207d9946/pypy/translator/sandbox$ ls
> autopath.py __init__.py interact.py rsandbox.py sandlib.py
> script.py vfs.py virtualtmp
> autopath.pyc __init__.pyc pypy_interact.py rsandbox.pyc sandlib.pyc
> test vfs.pyc
> kracekumar@python-lover:~/pypy-pypy-2346207d9946/pypy/translator/sandbox$ ls
> virtualtmp/
> script.py
> kracekumar@python-lover:~/pypy-pypy-2346207d9946/pypy/translator/sandbox$
> ./pypy_interact.py --tmp=virtualtmp pypy-c /tmp/script.py
> ['/bin/pypy-c', '/tmp/script.py']
> Traceback (most recent call last):
> File "./pypy_interact.py", line 121, in <module>
> tmpdir=tmpdir, debug=debug)
> File "./pypy_interact.py", line 44, in __init__
> executable=executable)
> File
> "/home/kracekumar/pypy-pypy-2346207d9946/pypy/translator/sandbox/sandlib.py",
> line 423, in __init__
> super(VirtualizedSandboxedProc, self).__init__(*args, **kwds)
> File
> "/home/kracekumar/pypy-pypy-2346207d9946/pypy/translator/sandbox/sandlib.py",
> line 147, in __init__
> env={})
> File "/usr/lib/python2.7/subprocess.py", line 679, in __init__
> errread, errwrite)
> File "/usr/lib/python2.7/subprocess.py", line 1239, in _execute_child
> raise child_exception
> OSError: [Errno 2] No such file or directory
>
> Inside sandlib at line no 146, added print args. am i missing some thing ?
> --
> Thanks & Regards
>
> "Talk is cheap, show me the code" -- Linus Torvalds
> kracekumar
> www.kracekumar.com
>
>
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>
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