On 30/08/13 12:58, Amaury Forgeot d'Arc wrote: > > 2013/8/30 Carl Friedrich Bolz <cfb...@gmx.de <mailto:cfb...@gmx.de>> > > Hi Alex, > > please revert this change, it can lead to combinatorial explosion: it > can give a bridge per pattern of where in the list the object is found. > > > Doesn't list.count() traverse all the list in all cases?
It looks like this: count = 0 i = 0 while i < self.length(): if space.eq_w(self.getitem(i), w_value): count += 1 i += 1 So there's a guard_true/false for every item. Note that even changing to: count += space.eq_w(self.getitem(i), w_value) does not fix this, because the guard is coming from inside space.istrue, or space.eq Cheers, Carl Friedrich _______________________________________________ pypy-dev mailing list pypy-dev@python.org http://mail.python.org/mailman/listinfo/pypy-dev