> > I have a button that used to be connected to accept() on a dialog. I > added some validation, and only want to call accept() now if the > validation passes. I tried calling dlg.accept() but I got the message > that it is not callable because it was not created in python. > > > > What is the work around?
QDialog::accept() is protected so it has to be exposed as public by a sub-class. This is handled automatically by SIP for QDialogs created from Python. Otherwise you will have to do it yourself in C++. Phil _______________________________________________ PyKDE mailing list [EMAIL PROTECTED] http://mats.imk.fraunhofer.de/mailman/listinfo/pykde
