On 28.11.07 10:40:58, Alexandre Badez wrote: > On Nov 28, 2007 10:21 AM, Horst Herb <[EMAIL PROTECTED]> wrote: > > > On Wednesday 28 November 2007, Alexandre Badez wrote: > > > wChapterSelection = QtGui.QDialog() > > > wChapterSelection.exec_() > > > > > > And I've got also a bus error. > > > > > > What really suprise me, is that I already use QDialog elsewhere, and I > > > didn't had any problem with this. > > > > app = QApplication(sys.argv) > > wChapterSelection = QtGui.QDialog() > > wChapterSelection.show() > > app.exec_() > > > > would work. > > I am a newbie to PyQt4, so I don't know whether you can just run a widget > > itself without creating an application first - but if you do, it works > > > Thanks Horst. > > I know it work, and I can do it as you type. > But the problem in your exemple, is that the show is not blocking so you can > do something like > > myDialog = myDialogClass() > > myDialog.exec_() > > if myDialog.result == myDialog.accept(): > # do something > else: > #do something else
But you can do this inside your dialog class. Just override the accept and reject methods and do whatever logic you have their. It doesn't make sense to have a modal dialog without another window (i.e. in your __main__ function), as then its not really modal. And making a modal dialog is exactly what the exec_() does. Andreas -- You're definitely on their list. The question to ask next is what list it is. _______________________________________________ PyQt mailing list [email protected] http://www.riverbankcomputing.com/mailman/listinfo/pyqt
