massimo di stefano wrote:
.. done little step ahead :
import sys
from PyQt4 import QtCore, QtGui
import time
class MyThread(QtCore.QThread):
def run(self):
n = 0
step = 1
while True:
n += step
print n
class Gui(QtGui.QWidget):
def __init__(self, parent=None):
QtGui.QGroupBox.__init__(self, parent)
self.gcenter = QtGui.QPushButton("X", self)
self.gcenter.setAutoRepeat(True)
guiLayout = QtGui.QGridLayout()
guiLayout.addWidget(self.gcenter,1,0)
self.setLayout(guiLayout)
self.thread = MyThread()
self.connect(self.gcenter, QtCore.SIGNAL("clicked()"),
self.thread.start)
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
gui = Gui()
gui.show()
sys.exit(app.exec_())
now i need to stop it when i "release" the button,
tried with :
self.connect(self.gcenter, QtCore.SIGNAL("released()"),
self.thread.quit)
but give :
AttributeError: stop
I'd suggest expanding your MyThread class to something like this:
class MyThread(QtCore.QThread):
def __init__(self, parent = None):
QtCore.QThread.__init__(self, parent)
self.running = 1
def run(self):
n = 0
step = 1
while self.running:
n += step
print n
self.msleep(100)
def stop(self):
self.running = 0
You should also look at the QtCore.QMutex() class, which provides a way
to synchronize (via locking) between the thread process and other processes.
-Hazen
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