Is there some reason new-style connection from any signal to
QSignalMapper.map do not appear to work?
Using old-style self.connect works, i.e.:
|
#self.connect(self.b1, SIGNAL("clicked()"),
# self.mapper, SLOT("map()"))
#self.connect(self.b2, SIGNAL("clicked()"),
# self.mapper, SLOT("map()"))
|
But using new-style self.<signal>.connect does not:
||| self.b1.clicked.connect(self.mapper.map)
self.b2.clicked.connect(self.mapper.map)
|
Here's a complete example:|
=========================================
from PyQt4.QtCore import *
from PyQt4.QtGui import *
app = QApplication([])
class Test(QWidget):
def __init__(self, parent=None):
super(Test, self).__init__(parent)
layout = QVBoxLayout()
self.b1 = QPushButton("B1")
self.b2 = QPushButton("B2")
layout.addWidget(self.b1)
layout.addWidget(self.b2)
self.setLayout(layout)
self.mapper = QSignalMapper(self)
self.mapper.setMapping(self.b1, "B1")
self.mapper.setMapping(self.b2, "B2")
self.b1.clicked.connect(self.mapper.map)
self.b2.clicked.connect(self.mapper.map)
#self.connect(self.b1, SIGNAL("clicked()"),
# self.mapper, SLOT("map()"))
#self.connect(self.b2, SIGNAL("clicked()"),
# self.mapper, SLOT("map()"))
self.mapper.mapped[QString].connect(self.sayIt)
@pyqtSlot(QString)
def sayIt(self, name):
print name
t = Test()
t.show()
app.exec_()
||=========================================|
cheers,
-Mark
--
Mark Visser, Software Director
Lumière VFX
Email: [email protected]
Phone: +1-514-316-1080 x3030
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