I'm running into an issue where when I remove the the scatterPlotItem from
GLViewWidget, it removes the grids from the view as well.
My code right now is way too long to post all of it but basically:
plotWidget = gl.GLViewWidget()
xgrid = gl.GLGridItem()
ygrid = gl.GLGridItem()
zgrid = gl.GLGridItem()
plotWidget.addItem(xgrid)
plotWidget.addItem(ygrid)
plotWidget.addItem(zgrid)
... create multiple glScatterPlotItems
with different pos, size, and color
plotList = [glScatterPlotItem1, glScatterPlotItem2,...]
# All scatter plots are added to the plot initially
for i in range(0, len(plotList)):
plotWidget.addItem(self.plotDic[k])
...depending on user input in MainWindow
for i in range(0, len(plotList)):
# This part is to remove all ScatterPlotItems from the
# widget so only the selected item will be visible.
# Because code does not know which one is added and which one is not.
# If there is a better way, please let me know
try:
plotWidget.removeItem(plotList[i])
print "removed: ", i, plotList[i] # to make sure I'm only removing
scatter plots
except ValueError:
pass
for i in range(0, len(plotList)):
if i == userInput: # only add the one that user selected
print "added: ", i, plotList[i]
plotWidget.addItem(plotList[i])
and assuming that there are only two GLScatterPlots are made at some point
and I run the script, it first adds both plots with the grids so no issue
there.
However, when the user selects "1" as their input, the Grid Items (all
three x, y, and z) are also removed along with "0" and only the scatter
plot for "1" remains in the widget/ I verified that the only items being
removed are the scatter plots with the print statements shown below:
# User first selects 0 which removes both 0 and 1 that were added initially
then adds 0 again
removed: 1 <pyqtgraph.opengl.items.GLScatterPlotItem.GLScatterPlotItem
object at 0x1136603e0>
removed: 0 <pyqtgraph.opengl.items.GLScatterPlotItem.GLScatterPlotItem
object at 0x113672808>
added: 0 <pyqtgraph.opengl.items.GLScatterPlotItem.GLScatterPlotItem object
at 0x113672808>
# User then selects 1 which removes 0 which is already in the widget then
adds 1
# However when 0 is removed, the grids are removed as well when the only
thing removed is the scatter plot
removed: 0 <pyqtgraph.opengl.items.GLScatterPlotItem.GLScatterPlotItem
object at 0x113672808>
added: 1 <pyqtgraph.opengl.items.GLScatterPlotItem.GLScatterPlotItem object
at 0x1136603e0>
# User then selects 0 again which removes 1 which was the only that was in
the grid widget
# However now with 0, the grids are now back. This attitude repeats. 0 and
grid go away together.
removed: 1 <pyqtgraph.opengl.items.GLScatterPlotItem.GLScatterPlotItem
object at 0x10eea83e0>
added: 0 <pyqtgraph.opengl.items.GLScatterPlotItem.GLScatterPlotItem object
at 0x10eeba808>
It does not matter whether the user selects 1 first or 0 first. I'm
obviously only removing the GLScatterPlotItems according to the print
statements but it seems that the first GLScatterPlot has some how fused
itself with the Grid Items as well. Is it an error on my end?
--
You received this message because you are subscribed to the Google Groups
"pyqtgraph" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to [email protected].
To view this discussion on the web visit
https://groups.google.com/d/msgid/pyqtgraph/c85928a3-32c7-4cfd-8b42-e3192e27a821%40googlegroups.com.
For more options, visit https://groups.google.com/d/optout.
