so i spent the weekend looking through somethings and it seems that i need to use a version of the affine slice function. however, in analyzing the code for this function i am having a hard time determining which lines correspond to the size of the array that is returned. Ideally, i would want a 1D array of coordinates that the line passes through. any help is appreciated. Jake
On Friday, August 5, 2016 at 1:30:48 PM UTC-5, Jacob Ricci wrote: > > > Hello, > I am new to pyqtgraph and python in general and i was wondering if you > could help me out a bit. I have an array of dicom images that I am able to > display using pyqtgraph.image(array) where 'array' contains my data and i > am able to scroll through them using the slider. However, i am wondering if > there is a way that I can draw a line through these images between two > arbitrary points. For example, in the data i am working with currently I > have two 3d points: (258,461,52) and (258,0,52). In this case, it would be > a vertical line at x=258 and at the 52 slice in the image set. Is there a > way to plot this line within the window that displays with the original > pyqtgraph.image(array) command? Also, it is not guaranteed that this line > will stay within the same image slice or be vertical/horizontal as it > depends on arbitrary angles in the xy and yz plane. I have tried using the > GLLinePlotItem but it is giving me trouble as im getting errors concerning > my pos argument. I expect that this comes for not being well enough versed > in python and not understanding the arguments. Any help would be greatly > appreciated. I am sorry if this is too vague I can explain further if > necessary. > Jake > -- You received this message because you are subscribed to the Google Groups "pyqtgraph" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To view this discussion on the web visit https://groups.google.com/d/msgid/pyqtgraph/a4155ab4-13c6-459a-9ecf-1b0bbb3687b6%40googlegroups.com. For more options, visit https://groups.google.com/d/optout.
