Hi all,
The code below works as expected to get the position of a click in a
GraphicsLayoutWidget. But if I uncomment the @pyqtSlot() line, then I get
the following error when I click in the GLW:
TypeError: onClick() missing 1 required positional argument: 'evt'
Should I not be using @pyqtSlot() decorator?
James
PS: I do not see an option to syntax-highlight code blocks in this group.
Can that be enabled?
import sys
import pyqtgraph as pg
from PyQt5 import QtWidgets as qtw
from PyQt5.QtCore import pyqtSlot
class MainWindow(qtw.QMainWindow):
def __init__(self, *args, **kwargs): super(MainWindow,
self).__init__(*args, **kwargs)
self.glw = pg.GraphicsLayoutWidget()
self.setCentralWidget(self.glw)
self.glw.scene().sigMouseClicked.connect(self.onClick)
self.show()
#@pyqtSlot()
def onClick(self, evt):
print("glw clicked")
print(evt.scenePos())
if __name__ == "__main__":
app = qtw.QApplication(sys.argv)
win = MainWindow()
app.exec_()
--
You received this message because you are subscribed to the Google Groups
"pyqtgraph" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to [email protected].
To view this discussion on the web visit
https://groups.google.com/d/msgid/pyqtgraph/45c00b31-e48e-4361-ac59-6b72bbc68530n%40googlegroups.com.