Hi Francesc,
Francesc Altet wrote:
> A Dimarts 22 Agost 2006 08:10, Jan Strube va escriure:
>
>> Oh, and yet another question:
>> In my structure, I have scalar and vectorial quantities. How can I
>> determine which is which on an unfilled table ?
>> I am trying row.getTable().col(column_name).ndim, but that seems only to
>>
>
> Please, don't use row.getTable() (it is not documented and, in fact, it is
> going to disappear in forthcoming PyTables 1.4 series). Instead, bind the
> table to a name (say, 'table') and use the more effective :
>
> table.col(column_name)
>
> as this saves quite a few name lookups.
>
>
Thanks for noting this. I thought that this didn't look right. I found
it via tab-completion in ipython...
>> work on filled tables. In my case it simply returns 1 for all columns.
>>
>> Is there a way to determine the dimension of the row I am currently
>> filling ?
>>
>
> This is because attribute .ndim of NumPy returns the *number* of dimensions
> of
> the object, and not the shape that it is what you want. Please note that,
> despite the fact that there is a number of different definitions for
> the "number of dimensions", in pythonic numerical packages this is always
> defined as len(shape).
>
> The best way of getting the shape for columns without doing an actual read of
> the data is accessing directly to the metadata of the Table object:
>
> print table.description.baryon2.decayVector.shape
>
> or
>
> print table.colshapes['baryon2/decayVector']
>
> Check the different attributes of Table in the manual (section 4.6.1)
> as well as the Description class (section 4.8) for more accessible metadata
> info.
>
> HTH,
>
Sure does.
Thanks,
Jan
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