Phillip J. Eby wrote: > Proceeding to the "Next" Method > ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ > > If the first parameter of an overloaded function is named > ``__proceed__``, it will be passed a callable representing the next > most-specific method. For example, this code:: > > def foo(bar:object, baz:object): > print "got objects!" > > @overload > def foo(__proceed__, bar:int, baz:int): > print "got integers!" > return __proceed__(bar, baz)
I don't care for the idea of testing against a specially named argument. Why couldn't you just have a different decorator, such as "overload_chained" which triggers this behavior? -- Talin _______________________________________________ Python-3000 mailing list Python-3000@python.org http://mail.python.org/mailman/listinfo/python-3000 Unsubscribe: http://mail.python.org/mailman/options/python-3000/archive%40mail-archive.com
