On Wed, Jan 09, 2008 at 11:26:52AM -0800, Bill Janssen wrote:
> I'm a bit baffled here; I find cmp() fairly handy in writing sort
> routines:
>
> newlist = oldlist.sort(lambda v1, v2: cmp(v1.attr_x, v2.attr_x))
>
> Is there a better / newer / official way of doing this?
newlist = oldlist.sort(key=lambda v: v.attr_x)
Oleg.
--
Oleg Broytmann http://phd.pp.ru/ [EMAIL PROTECTED]
Programmers don't die, they just GOSUB without RETURN.
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