Talin wrote: > > if a generator is yielding the > entire output of another generator, it might be possible to 'cut out the > middleman' and have the ultimate consumer of the values read the > innermost generator directly.
On the face of things, it certainly seems as though such a thing *ought* to be possible. It would require keeping a stack of generators somewhere, although I'm not sure exactly where. Perhaps each generator frame could have a "referral" slot which can contain a reference to another iterator. When a generator hits a "yield *" statement, it puts the argument into its referral slot. Then, the next() method of a generator would first run down the chain of referral slots until it gets to the end (either a generator with nothing in its referral slot, or a non-generator iterator), and resume the iterator found there. If it's found to be exhausted, you would back up to the previous one and resume that, etc., until you either get a value or the outermost generator is exhausted. Does that sound like it would be workable? -- Greg _______________________________________________ Python-3000 mailing list Python-3000@python.org http://mail.python.org/mailman/listinfo/python-3000 Unsubscribe: http://mail.python.org/mailman/options/python-3000/archive%40mail-archive.com
