2008/4/24, "Martin v. Löwis" <[EMAIL PROTECTED]>: > The advanced way of invoking some method on the object (i.e. emulating > the for loop) is to first create an iterator from the range object. > You can't consume the range itself: it will always contain the same > numbers - just like you can't consume a list.
Great! Thanks! >>> r = range(10000000000000000000) >>> it = iter(r) >>> it.__next__() 0 >>> it.__next__() 1 > >>>> r = range(10000000000000000000) > >>>> r[0] > > Traceback (most recent call last): > > File "<stdin>", line 1, in <module> > > OverflowError: Python int too large to convert to C ssize_t > > > > This is a bug, right? > > I'd call it an implementation limitation. This is because I'm in a 32 bit machine? >>> n = 10000000000000000000 >>> 2**32 > n False >>> 2**64 > n True Should it work in a 64 bit hardware? Thanks again! -- . Facundo Blog: http://www.taniquetil.com.ar/plog/ PyAr: http://www.python.org/ar/ _______________________________________________ Python-3000 mailing list Python-3000@python.org http://mail.python.org/mailman/listinfo/python-3000 Unsubscribe: http://mail.python.org/mailman/options/python-3000/archive%40mail-archive.com
