Bugs item #1155938, was opened at 2005-03-03 10:42
Message generated for change (Comment added) made by rhettinger
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Category: Type/class unification
Group: Python 2.4
>Status: Closed
>Resolution: Fixed
Priority: 5
Submitted By: Steve Alexander (stevea_zope)
Assigned to: Raymond Hettinger (rhettinger)
Summary: yield in __init__ causes broken new-style class
Initial Comment:
class Foo(object):
def __init__(self):
print "foo"
raise RuntimeError
yield 23
Foo()
With a classic class, this correctly fails saying
"__init__ must return None". With a new-style class,
the class suite works, and Foo() is called without
reporting an error, but also without printing "foo".
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>Comment By: Raymond Hettinger (rhettinger)
Date: 2005-03-03 11:56
Message:
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Fixed.
See typeobject.c 2.264 and 2.264.2.1.
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Comment By: Steve Alexander (stevea_zope)
Date: 2005-03-03 11:46
Message:
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Albertas Agejevas has pointed out that:
1. New style classes don't care what is returned from __init__.
2. If __init__ contains a yield, the code in __init__ won't
be called until the generator that is returned has its
'.next()' method called.
Which all makes sense. However, someone I work with was
trying for ages to work out what a particular __init__
method was not being called. The __init__ method was rather
long, and there was a yield, copy-pasted from some other
code, hidden behind a raise.
So, the behaviour may be correct, but I don't think it is
very helpful.
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Comment By: Michael Hudson (mwh)
Date: 2005-03-03 11:02
Message:
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You don't have to be that cute:
>>> class Foo(object):
... def __init__(self):
... return "foo"
...
where did that check go?
----------------------------------------------------------------------
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