Bugs item #1177811, was opened at 2005-04-06 14:30 Message generated for change (Tracker Item Submitted) made by Item Submitter You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=105470&aid=1177811&group_id=5470
Category: Python Interpreter Core Group: Python 2.4 Status: Open Resolution: None Priority: 5 Submitted By: Andrew Wilkinson (andrew_j_w) Assigned to: Nobody/Anonymous (nobody) Summary: Exec Inside A Function Initial Comment: When 'exec'ing code that creates a function inside a function the defined function (fact in the example below) is created with the module level namespace as it's parent scope. The following should return 2 however it raises a NameError as fact is not defined. def f(): exec """ def fact(x): if x==1: return 1 else: return x*fact(x-1) """ return fact f()(2) If you run following code... def f(): exec """ def fact(x): if x==1: return 1 else: return x*fact(x-1) """ in locals() return fact ... it works as expected. The documentation states that "In all cases, if the optional parts are omitted, the code is executed in the current scope." That is clearly not the case here as the 'fact' function is set with the module level scope as it's parent scope. It would appear to me that either this a documentation bug or a flaw in exec. I sincerely hope this a bug in exec and not the desired behaviour as it doesn't make any sense to me... ---------------------------------------------------------------------- You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=105470&aid=1177811&group_id=5470 _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
