Bugs item #1185883, was opened at 2005-04-19 12:07 Message generated for change (Comment added) made by krisvale You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=105470&aid=1185883&group_id=5470
Category: Python Interpreter Core Group: Python 2.3 Status: Open Resolution: None Priority: 5 Submitted By: Kristján Valur (krisvale) Assigned to: Tim Peters (tim_one) Summary: PyObject_Realloc bug in obmalloc.c Initial Comment: obmalloc.c:835 If the previous block was not handled by obmalloc, and the realloc is for growing the block, this memcpy may cross a page boundary and cause a segmentation fault. This scenario can happen if a previous allocation failed to successfully allocate from the obmalloc pools, due to memory starvation or other reasons, but was successfully allocated by the c runtime. The solution is to query the actual size of the allocated block, and copy only so much memory. Most modern platforms provide size query functions complementing the malloc()/free() calls. on Windows, this is the _msize () function. ---------------------------------------------------------------------- >Comment By: Kristján Valur (krisvale) Date: 2005-04-19 14:39 Message: Logged In: YES user_id=1262199 I can only say that I´ve been seeing this happeing with our software. Admittedly it's because we are eating up all memory due to other reasons, but we would like to deal with that with a MemoryError rather than a crash. ---------------------------------------------------------------------- Comment By: Michael Hudson (mwh) Date: 2005-04-19 14:30 Message: Logged In: YES user_id=6656 Tim, what do you think? This is a pretty unlikely scenario, it seems to me. ---------------------------------------------------------------------- You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=105470&aid=1185883&group_id=5470 _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
