Feature Requests item #1212091, was opened at 2005-05-31 17:54 Message generated for change (Comment added) made by birkenfeld You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=355470&aid=1212091&group_id=5470
Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Python Library Group: None Status: Open Resolution: None Priority: 5 Submitted By: Mike Coleman (mkc) Assigned to: Nobody/Anonymous (nobody) Summary: sets needs an 'arbitrary element' method Initial Comment: It would be nice to have an "arbitrary element" method that would return some arbitrary element of a non-empty set (throwing an exception if the set is empty). Something like this >>> s = sets.Set([1,2,3]) >>> print s.element() 2 AFAIK, the current alternative would be to do something like this >>> print list(s)[0] which is somewhat expensive and unreadable. It'd be fine if the operator returned the same or a different element each time. Perhaps it'd be useful if it returned the same element each time for frozen sets. ---------------------------------------------------------------------- >Comment By: Reinhold Birkenfeld (birkenfeld) Date: 2005-05-31 17:59 Message: Logged In: YES user_id=1188172 For mutable sets, I think that pop() is better suited. Do you have a use case of your proposal with frozensets? ---------------------------------------------------------------------- You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=355470&aid=1212091&group_id=5470 _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
