Daniel Urban <urban.dani...@gmail.com> added the comment: I found another case, when this is a problem: if there are no **kwargs, but there are some keyword-only arguments:
>>> def f(*, a, b): pass ... >>> f(a=1, b=2) >>> >>> getcallargs(f, a=1, b=2) Traceback (most recent call last): ... TypeError: f() takes no arguments (2 given) The attached issue11256_3.diff patch also fixes this problem, and adds tests that would have detected this case. ---------- Added file: http://bugs.python.org/file20930/issue11256_3.diff _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue11256> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com