Mark Dickinson <dicki...@gmail.com> added the comment: > it may be worth looking at what numpy does here.
... or it may not. NumPy just uses (approximation to 1/log(2)) * log(x) when log2 doesn't already exist. And indeed, on Windows: Python 2.7.1 |EPD 7.0-2 (64-bit)| (r271:86832, Dec 2 2010, 10:23:25) [MSC v.1500 64 bit (AMD64)] on win32 Type "help", "copyright", "credits" or "license" for more information. >>> import numpy >>> numpy.log2(8.0) 2.9999999999999996 I think we should be able to do better than this. :-) ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue11888> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
