Mark Dickinson <dicki...@gmail.com> added the comment:
I agree with you on the correct 8 output bytes. And those expected bytes are
exactly what struct.pack is producing here:
Python 2.7.2 |EPD 7.1-1 (32-bit)| (default, Jul 3 2011, 15:40:35)
[GCC 4.0.1 (Apple Inc. build 5493)] on darwin
Type "packages", "demo" or "enthought" for more information.
>>> import struct
>>> struct.pack('!d', 1.2345)
'?\xf3\xc0\x83\x12n\x97\x8d'
>>> len(struct.pack('!d', 1.2345))
8
>>> struct.pack('!d', 1.2345).encode('hex')
'3ff3c083126e978d'
I suspect that the confusion arises from the way the output string is
displayed: the 8 bytes in the output string are escaped if they're not
printable ASCII characters, and are displayed directly otherwise (notice the
'?' and the 'n', with codes 0x3f and 0x63 respectively).
----------
nosy: +mark.dickinson
resolution: -> invalid
status: open -> closed
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Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue12889>
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