Bugs item #1748292, was opened at 2007-07-05 12:10
Message generated for change (Comment added) made by doerwalter
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Category: Unicode
Group: Python 2.5
Status: Open
Resolution: None
Priority: 5
Private: No
Submitted By: Christoph Zwerschke (cito)
Assigned to: M.-A. Lemburg (lemburg)
Summary: str.join() intercepts UnicodeDecodeError raised by iterator
Initial Comment:
This is somewhat similar to #905389 which has already been fixed.
If you run the following two lines,
def gen(): raise UnicodeDecodeError
''.join(gen())
then instead of UnicodeDecodeError, you get:
TypeError: function takes exactly 5 arguments (0 given)
I found this bug in Python 2.3.5, 2.4.4 and 2.5.1 on Windows and Linux.
The bug appears exactly for UnicodeDecodeError,
UnicodeEncodeError, UnicodeTranslateError; all other exceptions work as
expected. You can verify this with the following program:
import exceptions
def gen(e): raise e
for e in dir(exceptions):
e = getattr(exceptions, e)
if type(e) != type(Exception):
continue
try:
''.join(gen(e))
except BaseException, f:
e = e.__name__
f = f.__class__.__name__
if e != f:
print e, f
----------------------------------------------------------------------
>Comment By: Walter Dörwald (doerwalter)
Date: 2007-07-05 13:07
Message:
Logged In: YES
user_id=89016
Originator: NO
This has nothing to do with str.join(). The following script raises the
same exception:
def gen():
raise UnicodeDecodeError()
gen()
The problem is exactly what the exception message states: the
UnicodeDecodeError constructor expects five arguments. The following
version raises the expected UnicodeDecodeError:
def gen():
raise UnicodeDecodeError('ascii', 'bytes', 0, 1, 'ouch')
gen()
----------------------------------------------------------------------
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