Matthew Barnett <pyt...@mrabarnett.plus.com> added the comment: This should answer that question:
>>> re.findall(r"[\A\C]", r"\AC") ['C'] >>> regex.findall(r"[\A\C]", r"\AC") ['A', 'C'] The behaviour of regex is intended to match that of re for backwards compatibility. ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue13899> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
