Martin v. Löwis added the comment: I now see the problem. What you want to do cannot possibly work.
You are trying to create a string object that is larger than 2GB; this is not possible on a 32-bit system (which I assume you are using). No matter how you modify the read() function, it would always return a string that is so large it cannot fit into the address space. This will be fixed in Python 2.6, which has a separate .open method, allowing to read the individual files in the zipfile as streams. ---------- nosy: +loewis versions: +Python 2.5 -Python 2.6 __________________________________ Tracker <[EMAIL PROTECTED]> <http://bugs.python.org/issue1060> __________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
