zulla <[email protected]> added the comment:
Hi. No, it's a patched version. It won't crash under circumstances like that
[1] and won't succeed with invalid input:
>>> import urlparse
>>> urlparse.urlparse("http://www.google.com:foo";)
ParseResult(scheme='http', netloc='www.google.com:foo', path='', params='',
query='', fragment='')
>>> urlparse.urlparse("http://www.google.com:foo";).port
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File
"/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urlparse.py",
line 105, in port
port = int(netloc.split(':')[1], 10)
ValueError: invalid literal for int() with base 10: 'foo'
>>>
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<http://bugs.python.org/issue14036>
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