Richard Oudkerk <shibt...@gmail.com> added the comment:
> conn = MySQLConn()
> start_thread1(conn)
> start_thread2(conn):
> while True:
> if os.fork() == 0: # child
> raise Exception('doom') # triggers destructor
There is no guarantee here that the lock will be held at the time of the fork.
So even if we ensure that a lock acquired before the fork stayed lock, we won't
necessarily get a deadlock.
More importantly, you should never fork without ensuring that you exit with
os._exit() or os.exec*(). So your example should be something like
conn = MySQLConn()
start_thread1(conn)
start_thread2(conn):
while True:
if os.fork() == 0: # child
try:
raise Exception('doom') # does NOT trigger destructor
except:
sys.excepthook(*sys.exc_info())
os._exit(1)
else:
os._exit(0)
With this hard exit the destructor never runs.
----------
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Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue6721>
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