Ezio Melotti added the comment:
Sorry, I misread your code, looks like you want the href *without* 'cve'.
In that case change my code to use "'cve' not in attrs['href']" (also avoid
using s.find('cve') == -1 , and use the more readable and idiomatic 'cve' not
in s ).
I think your original script doesn't work for two reasons:
1) you are looking for a table with class="tablesorter", but in the HTML the
table doesn't have that class, so self.is_table is never set to True;
2) you are finding the href of the <a> with a "style" attribute and correctly
setting it to self.href_name, but the value is then replaced by "" when the
following <a> without "style" is found;
That said, I still suggest you to abandon sgmllib and use HTMLParser, or
possibly an external module like BeautifulSoup or LXML.
----------
resolution: -> invalid
stage: -> committed/rejected
status: open -> closed
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<http://bugs.python.org/issue16513>
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