Antoine Pitrou added the comment:
Actually, wait() calls self._waiters.remove() without holding the lock. But I
think it could easily do so after taking the lock (since it takes it anyway
before returning).
Also, _waiters should better be a set, since wait() needs the associative
behaviour when unregistering a waiter.
notify() would then look like:
for i in range(n):
try:
waiter = self._waiters.pop()
except KeyError:
break
waiter.release()
and wait() would look like:
waiter = _allocate_lock()
waiter.acquire()
self._waiters.add(waiter)
self._release_save()
try:
return waiter.acquire(timeout)
finally:
self._acquire_restore()
self._waiters.discard(waiter)
----------
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Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue17385>
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