Antoine Pitrou added the comment:
I see no file descriptor leak myself:
>>> f = urllib2.urlopen("http://www.google.com";)
>>> f.fileno()
3
>>> os.fstat(3)
posix.stat_result(st_mode=49663, st_ino=5045244, st_dev=7L, st_nlink=1,
st_uid=1000, st_gid=1000, st_size=0, st_atime=0, st_mtime=0, st_ctime=0)
>>> del f
>>> os.fstat(3)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
OSError: [Errno 9] Bad file descriptor
Ditto with Python 3:
>>> f = urllib.request.urlopen("http://www.google.com";)
>>> f.fileno()
3
>>> os.fstat(3)
posix.stat_result(st_mode=49663, st_ino=5071469, st_dev=7, st_nlink=1,
st_uid=1000, st_gid=1000, st_size=0, st_atime=0, st_mtime=0, st_ctime=0)
>>> del f
>>> os.fstat(3)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
OSError: [Errno 9] Bad file descriptor
Furthermore, you can use the `with` statement to ensure timely disposal of
system resources:
>>> f = urllib.request.urlopen("http://www.google.com";)
>>> with f: f.fileno()
...
3
>>> os.fstat(3)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
OSError: [Errno 9] Bad file descriptor
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<http://bugs.python.org/issue1208304>
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