New submission from Yasuhiro Fujii:
Calling Tkinter.Tk() with baseName keyword argument throws UnboundLocalError on
Python 2.7.4.
A process to reproduce the bug:
>>> import Tkinter
>>> Tkinter.Tk(baseName="test")
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/python2.7/lib-tk/Tkinter.py", line 1748, in __init__
if not sys.flags.ignore_environment:
UnboundLocalError: local variable 'sys' referenced before assignment
A patch to fix the bug:
--- Lib/lib-tk/Tkinter.py.orig
+++ Lib/lib-tk/Tkinter.py
@@ -1736,7 +1736,7 @@
# ensure that self.tk is always _something_.
self.tk = None
if baseName is None:
- import sys, os
+ import os
baseName = os.path.basename(sys.argv[0])
baseName, ext = os.path.splitext(baseName)
if ext not in ('.py', '.pyc', '.pyo'):
----------
components: Tkinter
messages: 187418
nosy: y-fujii
priority: normal
severity: normal
status: open
title: Calling Tkinter.Tk() with a baseName keyword argument throws
UnboundLocalError
type: behavior
versions: Python 2.7
_______________________________________
Python tracker <[email protected]>
<http://bugs.python.org/issue17803>
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