Paul Hoffman added the comment:
I *think* what you are saying is that there will be no float16 type, but the
result of struct.unpack('eorwhatever', packed_stuff)[0] will be the same as
struct.unpack('f', packed_stuff)[0], yes? If so, that's what I wanted. I don't
want a new float16; I want the output of unpacking a half-precision to be the
same as unpacking the other two.
I didn't see a statement like that earlier in the thread, but I could have
missed it. Or maybe this was covered in msg132976?
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<http://bugs.python.org/issue11734>
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