New submission from Barry A. Warsaw: urllib.request.urlopen() takes a `timeout` argument with a default value, but the default value is "hidden" and undocumented. As implemented, the value is socket._GLOBAL_DEFAULT_TIMEOUT, but even this isn't really correct or useful.
The problem comes if you are passing a set of arguments to urlopen() and want to pass in a timeout that is the same as default. Because its undocumented, you have to UTSL to figure out what the value is, and then you have to use a non-public attribute of the socket module. It would be better if urlopen() was documented to default `timeout=None` meaning "use the default timeout". The implementation should then use socket.getdefaulttimeout() when timeout=None. The documentation should also be updated. Now if you want to call urlopen() with the default values, it would just be `urlopen(..., timeout=None, ...)` ---------- messages: 192773 nosy: barry priority: normal severity: normal status: open title: urlopen() has a hidden default for its timeout argument versions: Python 3.4 _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue18417> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
