Nikolaus Rath added the comment:
After thinking about this a bit more, I think this is actually a true bug in
OrderedDict(), and only option (a) or be (b) really fix it.
Rationale:
I would expect that for any OrderedDict d, and any function modify_dict(d), the
following assertion holds:
for key in d:
assert key in d
modify_dict(d)
..but this actually breaks for
def modify_dict(d):
del d[0]
del d[1]
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<http://bugs.python.org/issue19414>
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