New submission from João Bernardo:
>From the docs for built-in function "round":
"If ndigits is omitted, it defaults to zero"
(http://docs.python.org/3/library/functions.html#round)
But, the only way to get an integer from `round` is by not having the second
argument (ndigits):
>>> round(3.5)
4
>>> round(3.5, 1)
3.5
>>> round(3.5, 0)
4.0
>>> round(3.5, -1)
0.0
>>> round(3.5, None)
Traceback (most recent call last):
File "<pyshell#6>", line 1, in <module>
round(3.5, None)
TypeError: 'NoneType' object cannot be interpreted as an integer
Either the docs are wrong or the behavior is wrong. I think it's easier to fix
the former...
But also there should be a way to make round return an integer (e.g. passing
`None` as 2nd argument)
----------
assignee: docs@python
components: Documentation, Interpreter Core
messages: 205647
nosy: JBernardo, docs@python
priority: normal
severity: normal
status: open
title: Round default argument for "ndigits"
versions: Python 3.4
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Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue19933>
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