Armin Ronacher added the comment:
What it currently returns:
>>> from wsgiref.util import request_uri
>>> request_uri({
... 'wsgi.url_scheme': 'http',
... 'SCRIPT_NAME': '',
... 'PATH_INFO': '/\xe2\x98\x83',
... 'SERVER_PORT': '80',
... 'SERVER_NAME': 'localhost'
... })
'http://localhost/%C3%A2%C2%98%C2%83'
What it should return:
'http://localhost/%E2%98%83'
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<http://bugs.python.org/issue20138>
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