New submission from Chris Clark:
The documentation for smtplib.SMTP says "If the connect() call returns anything
other than a success code, an SMTPConnectError is raised." It doesn't
explicitly specify what happens when connect() raises instead of returns, but I
think either the documentation should mention "socket.timeout" or it should
raise SMTPConnectError.
Python 3.3.4 (default, Feb 11 2014, 15:56:08)
[GCC 4.8.2 20140206 (prerelease)] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> from smtplib import SMTP
>>> SMTP('a.com', timeout=1)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/python3.3/smtplib.py", line 241, in __init__
(code, msg) = self.connect(host, port)
File "/usr/lib/python3.3/smtplib.py", line 320, in connect
self.sock = self._get_socket(host, port, self.timeout)
File "/usr/lib/python3.3/smtplib.py", line 291, in _get_socket
self.source_address)
File "/usr/lib/python3.3/socket.py", line 435, in create_connection
raise err
File "/usr/lib/python3.3/socket.py", line 426, in create_connection
sock.connect(sa)
socket.timeout: timed out
----------
components: Library (Lib)
messages: 213321
nosy: Chris.Clark
priority: normal
severity: normal
status: open
title: smtplib.SMTP raises socket.timeout
type: behavior
versions: Python 3.3
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Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue20903>
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