STINNER Victor added the comment: > As an alternative, how about turning _source into a property?
A class or an instance property? A class property requires a metaclass. I guess that each namedtuple type requires its own metaclass, right? ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue19640> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
