Stefan Behnel added the comment:
catalog = xml.etree.ElementTree.parse('books.xml')
# This succeeds
for book in catalog.findall('book'):
print(book.tag)
This is a bit of a convenience break in the API. The "normal" way to do it
would be either catalog.getroot().findall('book') or
catalog.findall('/catalog/book'). There is not much use in requiring to include
the root element in the path expression, therefore it's allowed to leave it
out. Note that you can't use absolute path expressions on Elements, this is a
difference to the ElementTree object.
# This fails:
for book in catalog:
print(book.tag)
Iterating over an ElementTree? What would that even mean? Why would you expect
it to iterate over the children of the root Element, and not, say, all Elements
in the document? I think that ambiguity is a good reason to not make
ElementTree objects iterable.
# But for inner elements, we have more options
book = catalog.find('bk101')
for subelement in book:
print(subelement.tag)
> Note, the XML data model requires that the outermost element have some
> capabilities that inner elements don't have (such as comments and processing
> instructions). That said, the outer element shouldn't have fewer
> capabilities that the inner elements.
ISTM that you are misinterpreting the ElementTree object as representing the
document root whereas it actually represents the document. The root Element is
given by tree.getroot().
----------
nosy: +eli.bendersky, scoder
_______________________________________
Python tracker <[email protected]>
<http://bugs.python.org/issue21028>
_______________________________________
_______________________________________________
Python-bugs-list mailing list
Unsubscribe:
https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
