New submission from Mak Nazečić-Andrlon:
While searching for a way to work around the breakage of the Schwartzian
transform in Python 3 (and the resulting awkwardness if you wish to use heapq
or bisect, which do not yet have a key argument), I thought of the good old
IEEE-754 NaN. Unfortunately, that shouldn't work since lexicographical
comparisons shouldn't stop for something comparing False all the time.
Nevertheless:
>>> (1, float("nan"), A()) < (1, float("nan"), A())
False
>>> (0, float("nan"), A()) < (1, float("nan"), A())
True
Instead of as in
>>> nan = float("nan")
>>> (1, nan, A()) < (1, nan, A())
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: unorderable types: A() < A()
(As a side note, PyPy3 does not have this bug.)
----------
components: Interpreter Core
messages: 221600
nosy: Electro
priority: normal
severity: normal
status: open
title: Tuple comparisons with NaNs are broken
versions: Python 3.4
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Python tracker <[email protected]>
<http://bugs.python.org/issue21873>
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