Antony Lee added the comment:
Actually, that specific solution (using a helper method) will fail because
there may be unhashable params (due to unhashable default values or
annotations) among the keyword-only arguments, so it may not be possible to
build a frozenset (rather, one should compare the {param.name: param if
param.kind == KEYWORD_ONLY} dict). The frozenset approach still works for
computing the hash as this requires all params to be hashable anyways.
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<http://bugs.python.org/issue20334>
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