New submission from Jon Dufresne:
The csv.writer.writerow() does not accept a generator as input. I find this
counter-intuitive and against the spirit of similar APIs. If the generator is
coerced to a list, everything works as expected. See the following test script
which fails on the line "w.writerow(g)". In my opinion, this line should work
identically to the line "w.writerow(list(g))".
---
import csv
f = open('foo.csv', 'w')
w = csv.writer(f)
g = (i for i in ['a', 'b', 'c'])
w.writerow(list(g))
g = (i for i in ['a', 'b', 'c'])
w.writerow(g)
---
----------
components: Library (Lib)
messages: 233470
nosy: jdufresne
priority: normal
severity: normal
status: open
title: csv.writer.writerow() does not accept generator (must be coerced to list)
type: behavior
versions: Python 3.3
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Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue23171>
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