Evgeny Kapun added the comment:
Tracemalloc code:
import re
import signal
import tracemalloc
class AlarmError(Exception):
pass
def handle_alarm(signal, frame):
raise AlarmError
signal.signal(signal.SIGALRM, handle_alarm)
s1 = tracemalloc.take_snapshot()
for _ in range(20):
try:
signal.alarm(1)
re.match('(?:a|a|(?=b)){1000}', 'a'*999)
raise RuntimeError
except AlarmError:
pass
s2 = tracemalloc.take_snapshot()
res = s2.compare_to(s1, 'lineno')
for e in res[:10]:
print(e)
For me, it shows almost 3 MiB allocated in re.py.
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<http://bugs.python.org/issue23689>
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