Stefan Behnel added the comment:
Or, speaking of "division with remainder":
n, r = divmod(nom * 10**prec, den)
if r * 5 >= den:
n += 1
x = str(n)
print('%s.%s' % (x[:-prec], x[-prec:]))
... minus the usual off-by-one that the tests would quickly find :)
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