Martin Panter added the comment:
The first example seems to behave as I would expect. The UnboundLocalError is
raised by the print() call, because the “x” variable has been deleted by the
exception handler. Equivalent code without using “nonlocal”:
>>> def f():
... x = None
... try:
... raise Exception()
... except Exception as x:
... pass
... print("x", x) # UnboundLocal due to exception handler
...
>>> f()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "<stdin>", line 7, in f
UnboundLocalError: local variable 'x' referenced before assignment
In both cases, I think this is correct behaviour. See
<https://docs.python.org/3.4/reference/compound_stmts.html#except>, which says
“When an exception has been assigned using ‘as target’, it is cleared at the
end of the except clause.”
----------
nosy: +vadmium
resolution: -> not a bug
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Python tracker <[email protected]>
<http://bugs.python.org/issue24321>
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