New submission from July Tikhonov:
Documentation of Template says:
$identifier names a substitution placeholder matching a mapping key of
"identifier". By default, "identifier" must spell a Python identifier. The
first non-identifier character after the $ character terminates this
placeholder specification.
While it was true when these lines were written, Python 3 has greatly extended
identifier character set, and it no longer matches the set of characters used
by Template:
>>> Template('$foo123щъ').substitute(foo=1, foo123=2, foo123щъ=3)
'2щъ'
I propose clarifying documentation.
Actually extending character set is backward-incompatible, although it won't be
if restricted to "${identifier}" syntax.
----------
assignee: docs@python
components: Documentation
messages: 244607
nosy: docs@python, july
priority: normal
severity: normal
status: open
title: string.Template documentation incorrectly references "identifiers"
versions: Python 3.4, Python 3.5, Python 3.6
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Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue24351>
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