Steve Dower added the comment:
To be more specific, with patch 1 applied:
subprocess.call("start file a&b>x", shell=True)
is equivalent to typing the following at a command prompt:
start file a & b > x
That is, "start file a" and then do "b", redirecting the output from "b" to a
file named "x".
With the change to os.startfile, we can write it as this:
os.startfile("file", "open", "a&b>x")
Which matches what we intended above. (startfile implies "start <first
argument>", and passes the third argument to the launched program without
modification.)
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<http://bugs.python.org/issue25005>
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