Ezio Melotti added the comment:
As far as I understand, this is treated as "x < y < z" or "x == y == z":
>>> import ast
>>> ast.dump(ast.parse("1 < 2 < 3"))
'Module(body=[Expr(value=Compare(left=Num(n=1), ops=[Lt(), Lt()],
comparators=[Num(n=2), Num(n=3)]))])
>>> ast.dump(ast.parse("1 == 2 == 3"))
'Module(body=[Expr(value=Compare(left=Num(n=1), ops=[Eq(), Eq()],
comparators=[Num(n=2), Num(n=3)]))])'
>>> ast.dump(ast.parse("1 in 2 == 3"))
'Module(body=[Expr(value=Compare(left=Num(n=1), ops=[In(), Eq()],
comparators=[Num(n=2), Num(n=3)]))])'
The following code is also valid and works as expected:
>>> 1 in [1] in [[1]]
True
>>> 2 not in [1] in [[1]]
True
Your example yields an unexpected result, but I'm not sure if and how it can be
fixed.
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<http://bugs.python.org/issue25484>
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