Emanuel Barry added the comment: `sum` has an optional `start` parameter, which defaults to 0, and is used as the first item to add. Since timedeltas and ints are not interoperable, that means you have to explicitly tell sum what to use.
The following code works: >>> e=[datetime.timedelta(3), datetime.timedelta(5)] >>> sum(e, datetime.timedelta(0)) datetime.timedelta(8) This is not a bug, but maybe this could use a more descriptive error message? I don't know. ---------- nosy: +ebarry _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue25549> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
