Serhiy Storchaka added the comment:
The patch changes public interface. This breaks compatibility with third-party
codecs implementing it.
We have found other solution to iterencode/iterdecode problem. For example we
can buffer iterated values and encode with one step delay:
prev = sentinel = object()
for input in iterator:
if prev is not sentinel:
output = encoder.encode(prev)
if output:
yield output
prev = input
if prev is not sentinel:
output = encoder.encode(prev, True)
if output:
yield output
Or remember the previous value and use it to calculate the empty value at the
end (works only if input type supports slicing):
prev = sentinel = object()
for input in iterator:
output = encoder.encode(input)
if output:
yield output
prev = input
if prev is not sentinel:
output = encoder.encode(prev[:0], True)
if output:
yield output
----------
nosy: +doerwalter, lemburg
versions: +Python 3.6 -Python 3.5
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<http://bugs.python.org/issue23231>
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